X^-3+6=4x^2+12

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Solution for X^-3+6=4x^2+12 equation: 



X^-3+6=4X^2+12

We move all terms to the left:

X^-3+6-(4X^2+12)=0

We add all the numbers together, and all the variables

X-(4X^2+12)+3=0

We get rid of parentheses

-4X^2+X-12+3=0

We add all the numbers together, and all the variables

-4X^2+X-9=0

a = -4; b = 1; c = -9;
Δ = b2-4ac
Δ = 12-4·(-4)·(-9)
Δ = -143
Delta is less than zero, so there is no solution for the equation

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